Answer:389.26 N
Explanation:
Given
mass of crate [tex]m=40\ kg[/tex]
Force applied [tex]F=10\ N[/tex]
inclination of force [tex]\theta =35^{\circ}[/tex]
Usually Normal reaction is equal to the weight of the object but here a force is pulling crate in upward direction so effective weight is less than mg
From diagram Normal reaction is
[tex]N=mg-F\sin \theta [/tex]
[tex]N=40\times 9.8-10\sin (35)[/tex]
[tex]N=392-5.73[/tex]
[tex]N=389.26\ N[/tex]
Same Normal reaction is exerted by crate to the ground and by ground to the crate.
Answer:
386.26 N
Explanation:
let N be the normal reaction on the block. F is the force, f = 10 N, which is inclined at 35° with the horizontal.
Resolve the force, F into components.
According to the diagram
As the block in the equilibrium in vertical direction so the sum of the forces along the vertical direction remains zero.
So, N + F Sinθ = mg
N = 40 x 9.8 - 10 x Sin 35°
N = 392 - 5.74
N = 386.26 N
Thus, the normal reaction force is 386.26 N.
