The width of the squall line of the thunderstorms = 30 miles
The rate of precipitation = 1.5 inches per hour
The speed of the thunderstorms = 30 mph
So, the spuall line of 30 miles thunderstorms will be passed at a location in an hour with the speed of 40mph.
As the precipitation rate is 1.5 inches per hour, so the above location will be crossed in one hour by the thunderstorms, will get 1.5 inches of rainfall.
1.5 inches ain will fall at a location over which the storms pass if the storms move at 30 mph.
It is given that the line of thunderstorms is 30 miles wide and the rainfall rate everywhere within this band of thunderstorms is 1.5 inches per hour.
It is required to how much rain will fall at a location over which the storms pass if the storms move at 30 mph.
It is defined as the condensate water vapor that falls because of the gravitational force on the earth.
We have:
Line of thunderstorms = 30 miles wide
Rainfall rate = 1,5 inches per hour
The line of thunderstorms is oriented in a north-south direction and it moves due east.
Storms move at 30 mph
As the precipitation rate is 1.5 inches per hour and the speed of the storm is 30 mph it means the rainfall will be 1.5 inches.
Thus, 1.5 inches ain will fall at a location over which the storms pass if the storms move at 30 mph.
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