Answer:
±13 in³
Step-by-step explanation:
V =πr²h
Take differentials of each side.
dV = πrhdr
ΔV = πrhΔr
Data:
r = 4 in
h = 10 in
Δr = 0.1 in
Calculation
ΔV = πrhΔr = π × 4 in × 10 in × 0.1 in = 4π in³ ≈ 13 in³
The possible error in the volume of the cylinder is ±13 in³
