WILL GIVE BRAINLIEST IF CORRECT *URGENT*

Triangle FGH has vertices F (0, 4), G (0, -4), and H (8, -4). Find the center of the circle that circumscribes Triangle FGH.
Enter your coordinate in the following format "(x, y)" where you substitute your x value and y values inside the parentheses.

WILL GIVE BRAINLIEST IF CORRECT URGENT Triangle FGH has vertices F 0 4 G 0 4 and H 8 4 Find the center of the circle that circumscribes Triangle FGH Enter your class=

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Answer:

(4,0)

Step-by-step explanation:

Triangle FGH has vertices F (0, 4), G (0, -4), and H (8, -4).

The center of the circle that circumscribes Triangle FGH is the circumcenter of triangle FGH.

This is where the perpendicular bisector of FG (y=0) and the perpendicular bisector of GH(x=4) meets.

Therefore the required coordinates are (4,0)

In this exercise we have to use the knowledge of vertices to calculate the values ​​of X and Y, in this way we find that:

[tex](X,Y)=(4,0)[/tex]

First, analyzing the values ​​given in the statement, we have that the vertices of this triangle are:

  • F (0, 4)
  • G (0, -4)
  • H (8, -4).

This happen place the at right angles to bisector of FG (y=0) and the perpendicular bisector of GH(x=4) meets. Therefore the necessary match happen (4,0).

See more about triangles at brainly.com/question/25813512