Answer:
see the explanation
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form [tex]k=\frac{y}{x}[/tex] or [tex]y=kx[/tex]
In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin
Let
x -----> the amounts of ammonia in ml
y -----> the amounts of distilled water in ml
In this problem the relationship between variables, x, and y, represent a proportional variation
The constant of proportionality k is equal to
see the table
For x=2, y=100 ----> [tex]k=\frac{100}{2}=50[/tex]
For x=5, y=250 ----> [tex]k=\frac{250}{5}=50[/tex]
The linear equation is equal to
[tex]y=50x[/tex]
Complete the values in the table
For x=3 -----> [tex]y=50(3)=150\ mL[/tex]
For x=3.5 -----> [tex]y=50(3.5)=175\ mL[/tex]
For y=200 ----> [tex]200=50x[/tex] ----> [tex]x=200/50=4\ mL[/tex]
we have the point (2.5,125)
That means ----> There are 2,5 mL of ammonia and 125 mL of distilled water
The ratio of the y-coordinate to the x-coordinate is equal to the constant of proportionality k or slope of the linear equation
so
[tex]k=\frac{125}{2.5}=50[/tex]