Answer:
[tex]FeSO_{4},FeCH_{3}CO,Fe_{2}(SO_{4})_{3},Fe_{2}(CH_{3}CO)_{3}[/tex]
Explanation:
Empirical formula of ionic compound formed by two ions [tex]A^{x+}[/tex] and [tex]B^{y-}[/tex] is [tex]A_{y}B_{x}[/tex] (for [tex]x\neq y[/tex]) of AB (for x = y)
The above empirical formula is in accordance with charge neutrality principle
Here each cation ([tex]Fe^{3+}[/tex] and [tex]Fe^{2+}[/tex]) can form two ionic compounds by combining with two given anions ([tex]SO_{4}^{2-}[/tex] and [tex]CH_{3}CO^{2-}[/tex]).
So the four ionic compounds are: [tex]FeSO_{4},FeCH_{3}CO,Fe_{2}(SO_{4})_{3},Fe_{2}(CH_{3}CO)_{3}[/tex]
