Answer:
pickles and (b) the jar exerts on the can
Explanation:
pickles and (b) the jar exerts on the can
Explanation:
Given that,
Mass of can soup, [tex]m_1=0.18\ kg[/tex]
Mass of jar of pickles, [tex]m_2=0.34\ kg[/tex]
The distance between these two objects, d = 0.42 m
There exists a force of gravity between the can of soup and the jar of pickles. This force is given by :
[tex]F=\dfrac{Gm_1m_2}{d^2}[/tex]
[tex]F=\dfrac{6.67\times 10^{-11}\times 0.18\times 0.34}{(0.42)^2}[/tex]
[tex]F=2.31\times 10^{-11}\ N[/tex]
(a) So, the force of gravity the can of soup exerts on the jar of pickles is [tex]F=2.31\times 10^{-11}\ N[/tex].
(b) The force of gravity the jar exerts on the can is also [tex]F=2.31\times 10^{-11}\ N[/tex] due to the Newton's third law of motion.
