A 174 pound Jimmy Cheek is riding on a 54 ft diameter Ferris Wheel. The normal force on Jimmy Cheek is 146 pounds when Jimmy is at the top of the wheel. Determine the angular velocity of the Ferris Wheel.

Respuesta :

To solve this problem we will apply the concepts related to the balance of Forces, the centripetal Force and Newton's second law.

I will also attach a free body diagram that allows a better understanding of the problem.

For there to be a balance between weight and normal strength, these two must be equivalent to the centripetal Force, therefore

[tex]F_c = W-N[/tex]

[tex]m\omega^2r = W-N[/tex]

Here,

m = Net mass

[tex]\omega[/tex]= Angular velocity

r = Radius

W = Weight

N = Normal Force

[tex]m\omega^2r = 174-146[/tex]

The net mass is equivalent to

[tex]F = mg \rightarrow m = \frac{F}{g}[/tex]

Then,

[tex]m = \frac{174lb}{32.17ft/s^2}[/tex]

Replacing we have then,

[tex](\frac{174lb}{32.17ft/s^2})\omega^2 (54ft) =174lb-146lb[/tex]

Solving to find the angular velocity we have,

[tex]\omega = 0.309rad/s[/tex]

Therefore the angular velocity is 0.309rad/s