To solve this problem we will apply the concepts related to Energy in a photon and the electric potential energy. With these two definitions we can solve the first two points. The energy in a photon is described under the mathematical relationship
[tex]E = \frac{hc}{\lambda}[/tex]
Here,
E = Energy of photons
h = Planck's constant
c = Speed of light
[tex]\lambda =[/tex] Wavelength
At the same time the electric potential energy is defined as
E = qV
Where,
q = Charge of electron
V = Voltage
PART A ) The charge of the electron is a constant while the voltage was previously given, therefore
[tex]E = qV[/tex]
[tex]E = (1.6*10^{-19}C)(100*10^3V)[/tex]
[tex]E = 1.6*10^{-14}J (\frac{1eV}{1.6*10^{-19}J})[/tex]
[tex]E = 10^5eV[/tex]
PART B) From the first definition, about energy in a photon, we can use it to find the wavelength. Energy is therefore conserved, the previously found value will serve us for that variable. The other two terms are constant, so replacing
[tex]E = \frac{hc}{\lambda}[/tex]
[tex]1.6*10^{-14}J =\frac{(1.6*10^{-14}J)(3*10^8m/s)}{\lambda}[/tex]
[tex]\lambda = 1.24*10^{-11}m[/tex]
Therefore the wavelength of the X-ray is [tex]\lambda = 1.24*10^{-11}m[/tex]
The energy of the photon is 1.6 * 10^5 ev or 1.6 * 10^-14 J while the wavelength of the waves is 1.23 * 10^-13 m.
The x - ray is part of the group of the electromagnetic rays which is collectively called the electromagnetic spectrum. We have the applied voltage as 100 kV.
Hence;
E = qv = 1.6 * 10^-19 * 100 * 10^3 V = 1.6 * 10^5 ev or 1.6 * 10^-14 J
Hence, the most energetic x-ray photon it can produce is 1.6 * 10^5 ev or 1.6 * 10^-14 J.
Given that;
E = hc/λ
λ = E/hc
λ = 6.6 * 10^-34 * 3 * 10^8/1.6 * 10^-14 J
λ =1.23 * 10^-13 m
Learn more about x-rays: https://brainly.com/question/9743981
