Explanation:
The given data is as follows.
Charge (q) = 2 coulomb, Force (F) = 60 N
Now, it is known that the relation between electric field, force and charge is as follows.
Magnitude of electric field (E) = [tex]\frac{Force}{charge}[/tex]
Hence, putting the given values into the above formula as follows.
Electric field (E) = [tex]\frac{Force}{charge}[/tex]
= [tex]\frac{60 N}{2 C}[/tex]
= 30 N/C
Thus, we can conclude that the magnitude of the electric field at the place where the charge is located is 30 N/C.
The magnitude of the electric field at the place where the charge is located is 30 N/C
This is simply defined as the force per unit charge. Mathematically, it is expressed as:
E = F / Q
Where
E is the electric field strength
F is the force
Q is the charge
From the question given above, the following data were obtained:
E = F/Q
E = 60 / 2
E = 30 N/C
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