To solve this problem we will apply the equations related to the loss of heat produced in the mass and quantified by the latent heat. From this value it will be possible to find the energy of an atomic bomb and the release of energy. Let's start with the given values, latent heat required for condensation is
[tex]L_c = 2264.76KJ/Kg[/tex]
Amount of water in [tex]10km^3[/tex]of air
[tex]m = 10*(1000)^3*0.017[/tex]
[tex]m = 1.7*10^8kg[/tex]
Therefore the required amount heat release is
[tex]Q=mL[/tex]
[tex]Q = 1.7*10^8(2264.76)[/tex]
[tex]Q = 3.85*10^{11}kJ[/tex]
Now of the values given for the release of an atomic bomb and making the conversion to KiloJules we would have to
One atomic bomb release [tex]2*10^{10}kCal[/tex]
[tex]E = 2*10^{10}*4.184[/tex]
[tex]E= 8.368*10^{10}kJ[/tex]
Therefore to condense water
[tex]\eta = \frac{\text{Energy in thunerstrom}}{\text{Energy released by atomic bom}}[/tex]
[tex]\eta = \frac{3.85*10^11}{8.368*10^{10}}[/tex]
[tex]\eta = 4.6\text{bomb energy}[/tex]
