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A dog sits 1.5 m from the center of a merry-go-round. The merry-go-round is set in motion, and the dog's tangential speed is 1.5 m/s. What is the dog's centripetalacceleration?

Respuesta :

Dog's centripetal acceleration is 1.5 m/s²

Explanation:

Centripetal acceleration is given by

                    [tex]a=\frac{v^2}{r}[/tex]

Where v is the tangential velocity and r is the radius.

         Here

        Tangential velocity, v = 1.5 m/s

        Radius, r = 1.5 m

Substituting

        [tex]a=\frac{v^2}{r}\\\\a=\frac{1.5^2}{1.5}\\\\a=1.5m/s^2[/tex]

Dog's centripetal acceleration is 1.5 m/s²

The dog Centripetal acceleration is [tex]1.5m/s^{2}[/tex]

Centripetal acceleration :

It is given as,  [tex]a=\frac{v^{2} }{r}[/tex]

Where v is tangential speed and r is radius.

Given that, [tex]v=1.5m/s ,r=1.5m[/tex]

Substitute values in above relation.

                      [tex]a=\frac{(1.5)^{2} }{1.5} \\\\a=1.5m/s^{2}[/tex]

Learn more about the tangential velocity here:

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