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Suppose you start an antique car by exerting a force of 258 N on its crank for 0.270 s. What angular momentum is given to the engine if the handle of the crank?

Respuesta :

MechEngineer

Answer:

69.66 rad/s

Explanation:

Suppose the handle of the crank is L = 1 m long. We can calculate the torque:

T = F*L = 258*1 = 258 Nm

Then the angular momentum is given to the handle within 0.27 seconds is

[tex]M_{\alpha} = T*t = 258*0.27 = 69.66[/tex] rad/s

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