Respuesta :
Answer:
[tex]1.445\times 10^{23} [/tex] formula units of sodium chloride can be formed from 13.0 gram of ferric chloride.
Explanation:
Mass of ferric chloride = 13.0 g
Moles of ferric chloride = [tex]\frac{13.0 g}{162.5 g/mol}=0.08 mol[/tex]
1 mole of ferric chloride has three moles of chloride ions.Then 0.08 moles of ferric chloride will have :
[tex]3\times 0.08 mol=0.24 mol[/tex] of chloride
[tex]Na^++Cl^-\rightarrow NaCl[/tex]
1 mole of sodium ion reacts with 1 mole of chloride ion to form 1 mole of NaCl. Then 0.24 moles of chloride ion will give:
[tex]\frac{1}{1}\times 0.24 mol=0.24 mol[/tex] of NaCl
1 mole = [tex]N_A=6.022\times 10^{23} [/tex] molecules/ atoms
Number of NaCl molecules in 0.24 moles :
[tex]=6.022\times 10^{23}\times 0.24=1.445\times 10^{23} molecules[/tex]
[tex]1.445\times 10^{23} [/tex] formula units of sodium chloride can be formed from 13.0 gram of ferric chloride.
