Answer:
The maximum number of grams of PH₃ that can be formed is 6.79g
Explanation:
This is the reaction:
P₄ + 6H₂ → 4PH₃
Let's find out the limiting reactant so we can work with.
1 mol of P₄ = 123.88 g/m
6.2 g / 123.88 g/m = 0.05 moles
1 mof of H₂ = 2 g/m
4 g / 2g/m = 2 mol
Clearly the limiting reactant is the P₄ but let's demonstrate it
6 mol of hydrogen react with 1 mol of phosphorus
2 mol of hydrogen react with (2 .1)/6 = 0.333 moles of P₄
We don't have enough P₄, that's why it is the limiting.
1 mol of P₄ produce 4 moles of phosphine
0.05 moles of P₄ will produce, the quadruple = 0.2 moles
Let's determine the grams (moles . molar mass)
0.2 moles . 33.97 g/m = 6.79 g
