Respuesta :

veronicaculs

Answer:

[tex]\sqrt[5]{4^3}[/tex] and [tex]\sqrt[5]{64}[/tex]

Step-by-step explanation:

  • Both the  power and the root of a number aplied at the same time can be written or expressed in two different ways: [tex]\sqrt[n]{x^k}=x^{\frac{k}{n}}[/tex] indistinctly.
  • Because there is no difference in expressing the power of a number in a fractional form as shown before, the expression  [tex]4^{\frac{3}{5}}[/tex] equals the expression [tex]\sqrt[5]{4^3}[/tex].
  • Then, we already have two equals expressions: [tex]4^{\frac{3}{5}}[/tex] and [tex]\sqrt[5]{4^3}[/tex].
  • If we take the last expression [tex]\sqrt[5]{4^3}[/tex] and solve [tex]4^3=4\times4\times4=64[/tex], we get [tex]\sqrt[5]{64}[/tex], which is another equal expression for the incial [tex]4^{\frac{3}{5}}[/tex].

:

Answer:

and

Step-by-step explanation:

Both the  power and the root of a number aplied at the same time can be written or expressed in two different ways:  indistinctly.

Because there is no difference in expressing the power of a number in a fractional form as shown before, the expression   equals the expression .

Then, we already have two equals expressions:  and .

If we take the last expression  and solve , we get , which is another equal expression for the inicial.