Answer:
79.2 grams of oxygen gas are required to react with 22.50 grams of n-heptane.
Explanation:
[tex]C_7H_{16} + 11O_2\rightarrow 7CO_2 + 8H_2O[/tex]
Mass of n-heptane = 22.50 g
Moles of n-heptane = [tex]\frac{22.50 g}{100 g/mol}=0.2250 mol[/tex]
According to reaction 1 mole of n-heptane reacts with 11 moles of oxygen gas. then 0.2250 moles of n-heptane will react with:
[tex]\frac{11}{1}\times 0.2250 mol=2.475 mol[/tex] of oxygen gas
Mass of 2.475 moles of oxygen gas= 2.475 mol × 32 g/mol= 79.2 g
79.2 grams of oxygen gas are required to react with 22.50 grams of n-heptane.
