Answer
Assuming the mass of the car, m = 43000 kg
initial speed u = 0
vertical distance moved, h = 8.8 m
spring constant k = 5 x 10⁵ N / m
acceleration of gravity = 9.8 m/s²
From law of conservation of energy ,
Gravitational potential energy at starting position =potential energy of the spring at maximum compression
[tex]m g h =\dfrac{1}{2}k x^2[/tex]
[tex]x = \sqrt{\dfrac{2mgh}{k}}[/tex]
[tex]x = \sqrt{\dfrac{2\times 43000\times 9.8\times 8.8}{5\times 10^5}}[/tex]
x = 14.83 m
If the mass of the car is equal to 43000 Kg the spring is compressed to 14.83 m
