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Two identical blocks are connected to opposite ends of a compressed spring. the blocks initially slide together on a frictionless surface with a velocity v to the right. at some instant, the left block is moving at v/2 to the left and the other block is moving to the right. what is the speed of the center of the mass of they system at that instant?

Respuesta :

Answer:

v to the right.

Explanation:

If there is no external force on the system, then the velocity of the center of mass is constant.

The initial velocity of center of mass is v to the right. Therefore, the velocity of the center of mass at any point is v to the right.

onyebuchinnaji

The speed of the center of the mass of the system at that instant will move to the right.

The given parameters;

  • initial velocity of each block, = v to the right
  • later velocity of the left block = v/2

According to the principle of conservation of linear momentum, in the absence of external force, the total momentum of the system is constant.

[tex]v_{cm} = \frac{m_1v_1 + m_2v_2}{m_1 + m_2}[/tex]

At any instant, the velocity of the center mass of the blocks will be in direction with greater momentum (right with velocity v).

Thus, we can conclude that the speed of the center of the mass of the system at that instant will move to the right.

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