Respuesta :
Answer:
[tex]Probability=\frac{1}{21}\\\\Percentage\ chances\approx 4.76\%[/tex]
Step-by-step explanation:
Probability: Probability of an event to occur is given by:
[tex]P=\frac{Number\ Favourable\ outcomes}{Number\ of\ total\ outcomes}[/tex]
Probability of Wednesday:
[tex]Total\ number\ of\ outcomes=7(as\ there\ are\ 7\ days\ in\ a\ week)\\\\Favourable\ outcomes=1\ (only\ Wednesday)\\\\P(Wednesday)=\frac{Number\ of\ favourable\ outcomes}{Number\ of\ total\ outcomes}\\\\P(Wednesday)=\frac{1}{7}[/tex]
Probability of first day rainy:
[tex]Let\ probability=P\\\\It\ is\ given\ that\ \frac{1}{3}\ times\ the\ first\ day\ is\ rainy.\\\\P=\frac{1}{3}[/tex]
Probability that first day is rainy Wednesday:
Let probability[tex]=P[/tex]
Since these two events are independent
[tex]P=P(Wednesday)\times P(rainy)\\\\P=\frac{1}{7}\times \frac{1}{3}\\\\P=\frac{1}{21}[/tex]
Percentage chances of rainy Wednesday[tex]=\frac{1}{21}\times 100\approx4.76\%[/tex]
Answer:
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Step-by-step explanation: