Answer:
Perimeter of ΔABC is approximately equal to 14.2 units.
Step-by-step explanation:
Given:
A = (3,4)
B = (-1,1)
C =(-2,5)
We need to find the perimeter of ΔABC.
Solution We will first find the length of each side.
length of each side can be cal calculated by using distance formula of geometry which gives.
[tex]s = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Where;
s⇒ Length of the line.
By Using this formula we will find the length of each side.
Length of side AB = [tex]\sqrt{((-1)-3)^2+(1-4)^2}= \sqrt{(-4)^2+(-3)^2}=\sqrt{16+9}=\sqrt{25} = 5\ units[/tex]
Length of side BC = [tex]\sqrt{((-2)-(-1)^2+(5-1)^2}= \sqrt{(-1)^2+(4)^2}=\sqrt{1+16}=\sqrt{17} = 4.1\ units[/tex]
Length of side CA = [tex]\sqrt{((3)-(-2)^2+(4-5)^2}= \sqrt{(5)^2+(-1)^2}=\sqrt{25+1}=\sqrt{26} = 5.1\ units[/tex]
Now Perimeter of the triangle is given sum of all sides.
Perimeter of ΔABC = AB + BC + CA = 5 + 4.1 + 5.1 = 14.2 units
Hence Perimeter of ΔABC is approximately equal to 14.2 units.
