Respuesta :
I think you must set x equal 0 and then we get our point
Answer:
The degree of the function is 5.
The y-intercept is at (0,12).
Step-by-step explanation:
The given function is
[tex]f(x)=-(x+1)^{2}(2x-3)(x+2)^{2}[/tex]
The easiest way to know the degree of this function is by just adding up the exponents, observe that the first and third factor are square and the other one is linear.
If we sum 2 + 1 + 2 = 5.
Therefore, the degree of the function is 5.
Now, to find the y-intercept, we need to use [tex]x=0[/tex], replacing this we have
[tex]f(x)=-(x+1)^{2}(2x-3)(x+2)^{2}\\f(0)=-(0+1)^{2}(2(0)-3)(0+2)^{2}=-1(-3)(4)=12[/tex]
Therefore, the y-intercept is at (0,12).