Answer:
The empirical formula would be AlCl₃
Explanation:
The ratio of number of moles of each reacted specie can help to determine the empirical formula
moles of Al
[tex]mole = \frac{given mass (g)}{molecular mass (g/mole)}[/tex]
[tex]mole = \frac{6.75 g}{27.0 g /mole}[/tex]
[tex]moles of aluminium = 0.250[/tex]
moles of Cl
[tex]mole = \frac{given mass (g)}{molecular mass (g/mole)}[/tex]
[tex]mole = \frac{26.63 g}{35.5 g /mole}[/tex]
[tex]moles of chlorine = 0.750[/tex]
Ratio of moles
[tex]ratio = \frac{moles of Cl}{moles of Al}[/tex]
[tex]ratio = \frac{0.750}{0.250}[/tex]
[tex]ratio = 3[/tex]
Empirical formula
Calculation shows that the number of moles of chlorine are three times higher than aluminium, hence empirical formula would be AlCl₃
