1.8 pounds of coffee worth $ 1.50 per pound should be mixed with 1.2 pounds of coffee worth $ 2.00 per pound to obtain 3 pounds of a new blend worth $ 1.70 per pound
Solution:
Let "x" be the pounds of coffee worth $ 1.50 per pound
Then, (3 - x) be the pounds of coffee worth $ 2.00 per pound
So, "x" pounds of coffee worth $ 1.50 per pound should be mixed with (3 - x) pounds of coffee worth $ 2.00 per pound to obtain 3 pounds of a new blend worth $ 1.70 per pound
Therefore, a equation is framed as,
[tex]1.50 \times x + (3-x) \times 2.00 = 3 \times 1.70\\\\1.50x +2(3-x) = 5.1[/tex]
Solve the above equation for "x"
[tex]1.50x +2(3-x) = 5.1\\\\1.50x + 6 - 2x = 5.1\\\\-0.5x = 5.1 - 6\\\\-0.5x=-0.9\\\\0.5x = 0.9\\\\x = 1.8[/tex]
Therefore, we need 1.8 pounds of coffee worth $ 1.50 per pound
Then, (3 - x) = 3 - 1.8 = 1.2 pounds of coffee worth $ 2.00 per pound
