William will reach 12 minutes faster than before
Step-by-step explanation:
Given
Speed =s = 15 miles per hour
Distance = d = 12 miles
First of all we will find the time it takes William to reach school
So,
[tex]speed=\frac{distance}{time}\\s = \frac{d}{t}\\t = \frac{d}{s}\\t = \frac{12}{15}\\t = 0.8\ hours[/tex]
It takes William 0.8 hour to reach school at a speed of 15 miles per hour
Now,
If the speed is increased 5 miles, the new speed will be 20 miles per hour
So,
[tex]s_1 = 20\ mph\\d = 12\ miles[/tex]
So the time taken now will be:
[tex]s_1 = \frac{d}{t_1}\\t_1 = \frac{12}{20}\\t_1 = 0.6\ hours[/tex]
Converting time into minutes
As 1 hour = 60 minutes
So,
t = 0.8 * 60 = 48 minutes
t_1 = 0.6 * 60 = 36 minutes
So,
48-36 = 12 minutes
So,
William will reach 12 minutes faster than before
Keywords: Variables, speed, distance
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