Bismuth and fluorine react to form bismuth fluoride. If 41796 g of
bismuth reacts completely with 113.99 g of fluorine, how many grams of
bismuth fluoride are formed?

Respuesta :

The mass of bismuth fluoride formed is 41909.99 g

Explanation:

According to the law of conservation of mass, the total mass of the reactants in a chemical reaction must be equal to the total mass of the products after the reaction.

In this problem, we have:

  • Reactants: bismuth and fluoride
  • Products: bismuth fluoride

We also have:

  • Mass of bismuth: 41796 g
  • Mass of fluoride: 113.99 g

So, the total mass of the reactants is:

[tex]M=41796+113.99 =41909.99 g[/tex]

And therefore, the mass of bismuth fluoride formed is also 41909.99 g.

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