Answer:
The expression is
[tex]BC=\frac{3}{sin(38^o)}sin(66^o)[/tex]
[tex]BC=4.45\ units[/tex]
Step-by-step explanation:
we know that
In the triangle ABC
Applying the law of sines
[tex]\frac{AB}{sin(C)}=\frac{BC}{sin(A)}[/tex]
we have
[tex]AB=3\ units\\C=38^o\\A=66^o[/tex]
substitute the given values
[tex]\frac{3}{sin(38^o)}=\frac{BC}{sin(66^o)}[/tex]
Solve for BC
[tex]BC=\frac{3}{sin(38^o)}sin(66^o)[/tex]
[tex]BC=4.45\ units[/tex]
