Answer:
Mass = 32.13 g
Explanation:
Given data:
Mass of water produced = 30 g
Mass of nitric acid needed = ?
Solution:
Chemical equation:
4Zn + 10HNO₃ → 4Zn(NO₃)₂ + NH₄NO₃ + 3H₂O
Number of moles of water:
Number of moles = mass/molar mass
Number of moles = 30 g/ 18 g/mol
Number of moles = 1.7 mol
Now we will compare the moles of water with nitric acid.
HNO₃ : H₂O
10 : 3
1.7 : 3/10×1.7 = 0.51 mol
Mass of nitric acid:
Mass = number of moles × molar mass
Mass = 0.51 mol × 63.01 g/mol
Mass = 32.13 g
