Answer:
see the explanation
Step-by-step explanation:
we have
[tex]4x+2y=4[/tex] ----> equation of the line in standard form
Convert to slope intercept form
[tex]y=mx+b[/tex]
Isolate the variable y
Subtract 4x both sides
[tex]2y=-4x+4[/tex]
Divide by 2 both sides
[tex]y=-2x+2[/tex]
To make a table assume different values of x and substitute in the equation to solve for y
For x=-2 ----> [tex]y=-2(-2)+2=6[/tex]
For x=-1 ----> [tex]y=-2(-1)+2=4[/tex]
For x=0 ----> [tex]y=-2(0)+2=2[/tex]
For x=1 ----> [tex]y=-2(1)+2=0[/tex]
For x=2 ----> [tex]y=-2(2)+2=-2[/tex]
The table is
[tex]\left[\begin{array}{ccc}x&y\\-2&6\\-1&4\\0&2\\1&0\\2&-2\end{array}\right][/tex]
