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Hopping into your Porsche you floor it and accelerate at 12 m/s^2 without spinning the tires. Determine the minimum coefficient of static friction between the tires and the road needed to make this possible

Respuesta :

ohiekulous

Answer:

1.2

Explanation:

a = 12 m/s²

g = 10 m/s²

# = ?

F = #R

# = a/g

Lanuel

The minimum coefficient of static friction between the tires and the road is 1.23.

Given the following data:

  • Acceleration = 12 [tex]m/s^2[/tex]

We know that the acceleration due to gravity (g) of an object on planet Earth is equal to 9.8 [tex]m/s^2[/tex]

To determine the minimum coefficient of static friction between the tires and the road needed to make the above possible:

Mathematically, the force of static friction is given by the formula;

Fs = μFn

Where;

  • Fs represents the force of static friction.
  • μ represents the minimum coefficient of static friction.
  • Fn represents the normal force.

The magnitude of the force accelerating your Porsche is given by Newton's Second Law of Motion:

[tex]F = ma[/tex]

Also, the normal force, [tex]Fn = mg[/tex]

[tex]F_s = ma = umg\\\\a = ug\\\\u = \frac{a}{g}[/tex]

Substituting the given parameters into the formula, we have;

[tex]u = \frac{12}{9.8}[/tex]

Minimum coefficient of static friction, μ = 1.23

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