Answer:
The average angular acceleration of the skater is 0.98 rad/s².
Explanation:
Given:
Initial angular speed of the skater is, [tex]\omega_i=3.27\ rad/s[/tex]
Final angular speed of the skater is, [tex]\omega_f=7.77\ rad/s[/tex]
Time interval for the change is, [tex]t=4.6\ s[/tex]
We know that, average angular acceleration is given as the ratio of change of angular speed and the time interval.
Therefore, the average angular acceleration is given as:
[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}\\\\\\\alpha =\dfrac{7.77-3.27}{4.6}\\\\\alpha=\dfrac{4.5}{4.6}\\\\\alpha=0.98\ rad/s^2[/tex]
Hence, the average angular acceleration of the skater is 0.98 rad/s².
