Snail 3, trying to keep up with Snail 2, managed to get to
of 6 cm/min. Continuing his excellent effort, he crossed the finish line
with a velocity of 6 cm/min. Continuing his excellent
cm/min and gobbled the lettuce leaves at exactly 10:18 AM. What
with a velocity of 7.2 cm/min and gobbled the lettic
was the acceleration of the winning snail?

Respuesta :

Answer:

Acceleration is the change in velocity over the change in time = Δv/Δt.  To do these problems, you need to find out how much the speed changed and over what period of time it changed.

Snail 1 changes from 4 cm/min to 7 cm/min in 3 minutes.  Subtract the starting velocity (4 cm/min) from the ending velocity (7 cm/min) then divide by the time (3 min):

Snail 1 = (7 cm/min. - 4 cm/min)/(3 minutes) = ?    (remember to put down the units)

Snail 2 changed from 7 cm/min. down to 1 cm/min. in 3 minutes

Snail 2 = (1 cm/min. - 7 cm/min.)/(3 min.) = ?        (note that the acceleration is negative when you slow down)

I hope this helps you