The acceleration of the snail is [tex]-2 cm/min^2[/tex], or [tex]-5.6\cdot 10^{-6} m/s^2[/tex]
Explanation:
The acceleration of an object is given by the equation:
[tex]a=\frac{v-u}{\Delta t}[/tex]
where
v is the final velocity
u is the initial velocity
[tex]\Delta t[/tex] is the time taken for the velocity to change from u to v
For the snail in this problem, we have:
u = 7 cm/min (initial velocity at the 90 cm mark)
v = 1 cm/min (final velocity at the 93 cm mark)
[tex]\Delta t = 3 min[/tex] (time interval between the snail being at the 90 cm mark and at the 93 cm mark)
Substituting into the equation, we find the acceleration of the snail:
[tex]a=\frac{1-7}{3}=-2 cm/min^2[/tex]
And converting into SI units,
[tex]a= -2 \frac{cm}{min^2} \cdot \frac{0.01 m/cm}{(60 sec/min)^2}=-5.6\cdot 10^{-6} m/s^2[/tex]
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