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PLEASE HELP!!
I DON'T HAVE A LOT OF POINTS LEFT AND THIS IS ALL I CAN OFFER!! :(
Write an equation of a line parallel to line EF in slope-intercept form that passes through the point (2, 6).

Line EF is shown. E is at negative 2, 5. F is at 1, 3.

y = 2x + 3
y = 3x + 6
y = negative two over 3x + twenty two over three
y = − two over threex + 6

Respuesta :

The equation of the parallel line is y = [tex]\frac{-2}{3}[/tex]  x + [tex]\frac{22}{3}[/tex] 3rd answer

Step-by-step explanation:

Parallel lines has:

  • Same slopes
  • Different y-intercepts

The slope-intercept form of the equation of a line is y = mx + b, where

  • m is the slope of the line and b is the y-intercept
  • The formula of m is [tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

∵ Line EF has E (-2 , 5) and F (1 , 3)

∴ [tex]x_{1}[/tex] = -2 and [tex]x_{2}[/tex] = 1

∴ [tex]y_{1}[/tex] = 5 and [tex]y_{2}[/tex] = 3

- Use the formula of m above to find the slope of line EF

∴ [tex]m_{EF}=\frac{3-5}{1--2}=\frac{-2}{3}[/tex]

∵ The line is parallel to line EF

∴ Their slopes are equal

∴ The slope of the parallel line is [tex]\frac{-2}{3}[/tex]

- Substitute the slope of the line in the form of the equation

∴ y = [tex]\frac{-2}{3}[/tex] x + b

- To find b substitute x and y in the equation by the coordinates

   of a point on the line

∵ The parallel line passes through point (2 , 6)

∴ x = 2 and y = 6

∴ 6 = [tex]\frac{-2}{3}[/tex] (2) + b

∴ 6 = [tex]\frac{-4}{3}[/tex] + b

- Add [tex]\frac{4}{3}[/tex] to both sides

∴ [tex]\frac{22}{3}[/tex] = b

∴ y = [tex]\frac{-2}{3}[/tex]  x + [tex]\frac{22}{3}[/tex]

The equation of the parallel line is y = [tex]\frac{-2}{3}[/tex]  x + [tex]\frac{22}{3}[/tex]

Learn more:

You can learn more about the equations of the parallel lines in brainly.com/question/9527422

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Answer:

3rd Choice

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