John painted his most famous work,in his country,in 1930 on composition board with perimeter 103.48 in. If the rectangular painting is 5.83 in. Taller it is wide,find the dimensions of the painting. what is the width? what is the length?

Respuesta :

Answer:

Width [tex]=22.955[/tex] in

length [tex]=28.785[/tex] in

Step-by-step explanation:

let width[tex]=x[/tex]

painting is [tex]5.83[/tex] in taller than it is wide

length [tex]=x+5.83[/tex]

Perimeter of rectangle [tex]=2[/tex] (length+width)

Perimeter of painting [tex]=103.48[/tex]

[tex]2(x+x+5.83)=103.48\\2x+5.83=51.74\\2x+51.74-5.83\\2x=45.91\\x=\frac{45}{2} \\x=22.955[/tex]

width [tex]=x=22.955[/tex] in

length [tex]=x+5.83=22.955+5.83=28.785[/tex] n