Answer:
b.(12.7350,16.5984)
Step-by-step explanation:
First, find the average and standard deviation of the sample:
x = 14.6667
s = 2.4618
To make a confidence interval of the population:
(μ ± MoE)
where:
μ = x
MoE = CV × s / √n
MoE is the margin of error, CV is the critical value, and s/√n is the standard error.
Looking in a student's t-table, for a 98% confidence interval, and for 12-1=11 degrees of freedom, CV = 2.718.
So the margin of error is:
MoE = 2.718 × 2.4618 / √12
MoE = 1.9316
The confidence interval is therefore:
(14.6667 ± 1.9316)
(12.7351, 16.5983)
