Answer:
The function h⁻¹(x) is [tex]h(x)=\{(-5,3),(-7,5),(-9,6),(-12,10),(-16,12)\}[/tex].
Step-by-step explanation:
If a function is defined as
[tex]f(x)=\{(x,y):x\in R,y\in R\}[/tex]
Then,
[tex]f^{-1}(x)=\{(y,x):x\in R,y\in R\}[/tex]
The given function is
[tex]h(x)=\{(3,-5),(5,-7),(6,-9),(10,-12),(12,-16)\}[/tex]
Interchange the x and y coordinates of each point to find the h⁻¹(x).
[tex]h(x)=\{(-5,3),(-7,5),(-9,6),(-12,10),(-16,12)\}[/tex]
Therefore the function h⁻¹(x) is [tex]h(x)=\{(-5,3),(-7,5),(-9,6),(-12,10),(-16,12)\}[/tex].
