Respuesta :
Answer:
-0.25
Step-by-step explanation:
Coordinates of C = [tex](x_{1} ,y_{1} )=(1,2)[/tex]
Coordinates of D = [tex](x_{2} ,y_{2} )=(-4,-2)[/tex]
Let Coordinates of A= (x,y)
Since A point is located 1/4 the distance from C to D
So the remaining distance from point A to D is 3/4
Thus the ratio of CA : AD = m:n=1:3
Now to find points of A we will use section formula i.e.
[tex]x=\frac{mx_{2}+nx_{1}}{m+n}[/tex]
[tex]y=\frac{my_{2}+ny_{1}}{m+n}[/tex]
Substituting the values:
[tex]x=\frac{1*-4+3*1}{1+3}[/tex]
[tex]x=\frac{-1}{4}[/tex]
[tex]x=-0.25[/tex]
Thus Find the x value for the point that is 1 over 4 the distance from point C to point D is -0.25
Hence option a is correct
