Answer:
The given line segment whose end points are A(2,2) and B(3,8).
Distance AB is given by distance formula , which is
if we have to find distance between two points (a,b) and (p,q) is
= [tex]\sqrt{(p-a)^2+(q-b)^2}[/tex]
AB= [tex]\sqrt{(3-2)^2+(8-2)^2}=\sqrt{1+36}=\sqrt{37}[/tex] = 6.08 (approx)
Line segment AB is dilated by a factor of 3.5 to get New line segment CD.
Coordinate of C = (3.5 ×2, 3.5×2)= (7,7)
Coordinate of D = (3.5×3, 3.5×8)=(10.5,28)
CD = AB × 3.5
CD = √37× 3.5
= 6.08 × 3.5
= 21.28 unit(approx)
2. Slope of line joining two points (p,q) and (a,b) is given by
m=[tex]\frac{q-b}{p-a}[/tex]
m= [tex]\frac{8-2}{3-2}=6[/tex]
As the two lines are coincident , so their slopes are equal.
Slope of line AB=Slope of line CD = 6
