Answer:
moles = 0.0035 moles
Explanation:
In order to use this, we need to use the expression to calculate the moles of any compound, which is:
n = m/MM (1)
Where:
n: moles
m: mass of the compound (in grams)
MM: Molecular mass of compound (grams per mole)
Now, we have the mass of the sucrose, but we do not have the molecular mass. To calculate it, we need to use the atomic weights of each indivual element of the compound. In this case, C, H and O.
The atomic weights that I'll use will be rounded, and they are:
C = 12 g/mol
H: 1 g/mol
O: 16 g/mol
Now, let's calculate the molar mass of sucrose
MMSucrose:
C = 12 * 12 = 144
H = 1 * 22 = 22
O = 16 * 11 = 176
MM = 144 + 22 + 176 = 342 g/mol
We have the molar mass, let's calculate the moles now, using (1):
n = 1.202 / 342
n = 0.0035 moles
