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24.08 x 10^23 atoms of Boron (B) is equal to how many moles of Boron?

a. 2 moles
b. 4 moles
c. 12 moles
d. 6.02 x 10^23 moles

Respuesta :

Willchemistry
1 mole ----------- 6.02 x 10²³ atoms
? mole ---------- 24.08 x 10²³ atoms

moles B = ( 24.08 x 10²³) x 1 / 6.02 x 10²³

moles B = 24.08 x 10²³ / 6.02 x 10²³

= 4 moles

Answer B

hope this helps!

Answer:

4 moles.

Explanation:

We know that the number of atoms in a mole of a substance = Avagadro's number = [tex]6.023X10^{23}[/tex]

the moles of boron containing [tex]24.08X10^{23}[/tex] atoms will be:

[tex]moles=\frac{numberofboronatoms}{avagadro'snumber}=\frac{24.08X10^{23}}{6.023X10^{23}}=3.99=4[/tex]

Thus there will be four moles in the given atoms of boron.

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