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At a temperature of 280k, the gas in a cylinder has a volume of 20.0 liters.

If the volume of the gas is decreased to 10.0 liters, what must the temperature be for the gas to remain at a constant pressure?

Respuesta :

Temperature should be 140k to maintain constant pressure

Answer:

T = 140 K

Explanation:

As we know by ideal gas law

[tex]PV = nRT[/tex]

now if pressure of the gas is constant

then we will have

[tex]V = \frac{nR}{P} T[/tex]

now we have

[tex]V_1 = 20.0 litre[/tex]

[tex]T_1 = 280 K[/tex]

[tex]V_2 = 10.0 litre[/tex]

now from above equation

[tex]\frac{20.0}{10.0} = \frac{280}{T}[/tex]

[tex]T = 140 K[/tex]

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