Answer:
Explanation:
Given data:
Mass of sample = 0.673 g
Volume = 250.0 mL (0.25 L)
Temperature = 83°C (273+83= 356 k)
Pressure = 747 torr (747/760 = 0.98 atm)
Gas type = ?
Solution:
PV = nRT
n = PV/RT
n = 0.98 atm× 0.25 L / 0.0821 atm. L/mol.K × 356 k
n = 0.245 / 29.23/mol
n = 0.01 mol
Number of moles = mass/ molar mass
Molar mass = 0.673 g / 0.01 mol
Molar mass = 67.3 g/mol
molar mass of CO2 = 44 g/mol
molar mass of H2 = 2.016 g/mol
molar mass of SO3 = 80.066 g/mol
molar mass of Ar = 40 g/mol
molar mass of Xe = 131.3 g/mol
So non of these gases are present.