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Neetoo

Answer:

Mass = 4.6 g

Explanation:

Given data:

Number of molecules of sucrose = 8.1 ×10²¹ molecules

Mass of sucrose = ?

Solution:

First of all we will calculate the number of moles by using Avogadro number.

1 mole × 8.1 ×10²¹ molecules / 6.022×10²³ molecules

1.35 × 10⁻² mol

Mass of sucrose:

Mass = number of moles × molar mass

Molar mass = 342.3 g/mol

Mass = 1.35 × 10⁻² mol ×342.3 g/mol

Mass = 462.1  × 10⁻² g

Mass = 4.6 g

samueladesida43

The mass in grams of 8.1 x 10²¹ molecules of sucrose (C12H22011) is 4.62g.

HOW TO CALCULATE MASS:

  • The mass of a substance can be calculated by multiplying the number of moles by its molar mass. That is;

  • mass (g) = no. of moles (mol) × molar mass (g/mol).

  • However, the number of moles must be calculated by dividing the number molecules in the compound by Avogadro's number:

  • no. of moles = 8.1 x 10²¹ ÷ 6.02 × 10²³

  • no. of moles = 1.35 × 10-²moles

  • Molar mass of (C12H22011) = 12(12) + 1(22) + 16(11)

= 144 + 22 + 176

= 342g/mol

  • mass (g) = 0.0135mol × 342g/mol

  • mass (g) = 4.62g

  • Therefore, the mass in grams of 8.1 x 10²¹ molecules of sucrose (C12H22011) is 4.62g.

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