Answer:
Alloy A weighs 18 g
Alloy B weighs 6 g
Step-by-step explanation:
Let the weight of Alloy A be "x" g and Alloy B be "y" g.
It is given that Alloy A is composed of 3 parts gold and 1 part silver and Alloy B is composed of 1 part good and 3 parts silver.
The total gold is given by,
= [tex](\frac{3}{4})(x) + \frac{1}{4}(y)[/tex] = 15 g
The total silver is given by,
= [tex](\frac{1}{4})(x) + \frac{3}{4}(y)[/tex] = 9 g
adding both the equations we get,
[tex]x+y = 24[/tex]
and subtracting we get,
[tex]x-y = 12[/tex]
Thus, by solving we get,
x=18 and y=6.
