Respuesta :

Answer:

Step-by-step explanation:

Gradient of a line =( y2 - y1)/x2 - x1

From the question, x1=4,y1=-1,x2=1,y2=0.

Therefore, substitute for these values in the above formula

m = 0-(-1)/1-4

= 0+1/-3

= -1/3.

Therefore, y-y1/x-x1 = -1/3

y - y1 = -1/3(x - x1)

y - (-1) = -(x-x1)/3

y+1 = - (x - 4)/3

Multiply through by 3

3y+3= -x+4

3y +x=4-3

x+3y= 1

Therefore the answer is A.

The required equation of the line passing through the points (4, -1) and (1, 0) is x + 3y = 1

The correct option is (A).

Equation of a Line:

If any line passing through the points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] then the equation of the line is

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

How to calculate equation of the line?

Here we have given that the points [tex](x_1,y_1)=(4, -1)[/tex] and [tex](x_2,y_2)=(1, 0)[/tex]

Therefore substitute into the above formula we have

[tex]y+1=\frac{0+1}{1-4}(x-4)[/tex]

[tex]y+1=\frac{1}{-3}(x-4)[/tex]

[tex]-3y-3=x-4[/tex]

[tex]x+3y=1[/tex]

The correct option is (A)

This is the conclusion to the answer.

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