The cost of 4 tickets will be $75.
Step-by-step explanation:
Given,
Cost of 5 tickets = $93
Cost of 3 tickets = $57
Let,
x be the cost of one ticket.
y be the fixed fee to every order.
According to given statement;
5x+y=93 Eqn 1
3x+y=57 Eqn 2
Subtracting Eqn 2 from Eqn 1;
[tex](5x+y)-(3x+y)=93-57\\5x+y-3x-y=36\\2x=36[/tex]
Dividing both sides by 2
[tex]\frac{2x}{2}=\frac{36}{2}\\x=18[/tex]
Putting x=18 in Eqn 1;
[tex]5(18)+y=93\\90+y=93\\y=93-90\\y=3[/tex]
Therefore,
Cost of 4 tickets = 4x+y = 4(18)+3 = 72+3 = $75
The cost of 4 tickets will be $75.
Keywords: linear equation, elimination method
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