Respuesta :
Answer:
Step-by-step explanation: Answer: y= 4 and x= 0.
There are two linear equations given in this question.
Let 12x-5y= -20 be equation 1 and y= x + 4 be equation 2
Therefore, substitute y= x+4 in equation 1 (i.e 12x-5y= -20)
Which gives us 12x-5(x+4)= -20
Then open the parentheses, we have
12x-5x-20= -20, then
7x-20= -20
Therefore add 20 to both sides
7x-20+20= -20+20
7x+0=0
Then we have 7x=0
Divide both sides by 7
x =0
Substitute for x=0 in any of the equations above.
I chose equation 2
Which is y= x+4
Therefore y= (0)+4
Then y= 4
If you choose equation 1
12x -5y=-20
Substituting x=0
we have 12(0) -5y= -20
Then -5y = -20
Divide both sides by -5
y = -20/-5
then y=4
Answer:
x=0, y=4
Step-by-step explanation:
given 12x-5y=-20...........(1)
y=x+4...................(2)
y=x+4 put in equ (1)
12x-5(x+4)=-20
12x-5x-20=-20
x= 0
x=0 put in equ (1)
0-5y=-20
y=[tex]\frac{-20}{-5}[/tex]
y=4
hence x=0, y=4 answer
