The cube root of given expression is: [tex]6x^3y^6[/tex]
Step-by-step explanation:
Given expression is:
[tex]216x^9y^{18}[/tex]
As we have to find the cube root of the given expression.
Taking cube root
[tex]\sqrt[3]{216x^9y^{18}}[/tex]
The cube root is changed to exponent of 1/3
So,
[tex]=(216x^9y^{18})^{\frac{1}{3}}\\=(6^3 . x^9 . y^{18})^{(\frac{1}{3})}\\= 6^{3*\frac{1}{3}}. x^{9*\frac{1}{3}} . y^{18*\frac{1}{3}}\\=6x^3y^6[/tex]
The cube root of given expression is: [tex]6x^3y^6[/tex]
Keywords: Cube root, polynomials
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