Answer:
x = [tex]$ \frac{40}{41} $[/tex]
y = [tex]$ \frac{58}{41} $[/tex]
Step-by-step explanation:
A system of two equation with two variables is given.
We solve it by eliminating one variable first.
The equations are:
[tex]$ 7x - 2y = 4 \hspace{20mm} \hdots (1) $[/tex] and
[tex]$ 3x + 5y = 10 \hspace{20mm} \hdots (2) $[/tex]
We can eliminate either x or y.
We will eliminate y.
To do that multiply Equation (1) by 5 and Equation (2) by 2.
We get: [tex]$ 35x - 10y = 20 $[/tex] and
[tex]$ 6x + 10y = 20 $[/tex]
Adding these two equations, we get:
[tex]$ 35x + 6x = 40 $[/tex]
[tex]$ \implies 41x = 40 $[/tex]
⇒ x = 40/41
We substitute the value of 'x' in Equation (1) (Can be substituted in Equation (2) as well). We get:
2y = 7x - 4
⇒ 2y = [tex]$7(\frac{40}{41}) - 4 $[/tex]
[tex]$ \implies y = \frac{140 - 82}{41} $[/tex]
[tex]$ \implies y = \frac{58}{41} $[/tex]
Therefore, (x, y) = (40/41, 58/41).
Answer:The correct answer to this problem is letter D {(40/41, 58/41})
Step-by-step explanation:
Had this on a quiz got it right
